Ekpresyon kayèm nonm premye ki siperyè ou byen egal ak yon antye natirèl n ke yo ba nou davans: Diferans ant vèsyon yo
Contenu supprimé Contenu ajouté
Aucun résumé des modifications |
|||
Liy 2 :
Nou ka fè pou pi piti twa gwoup apròch
<math>P_K\left(n\right) = \left(\sum_{i=1}^{2^k\times n}{\left(\left[\frac{1+\sum_{m=1}^{i}{\left(1 - \left[\frac{\left[\frac{{\left(m!\right)}^2}{m^3}\right]}{\frac{{\left(m!\right)}^2}{m^3}}\right]\right)}}{k + 1 + \sum_{m=1}^n{\left(1 - \left[\frac{\left[\frac{{\left(m!\right)}^2}{m^3}\right]}{\frac{{\left(m!\right)}^2}{m^3}}\right]\right)}} \right]\times \left[\frac{k + 1 + \sum_{m=1}^{n}{\left(1 - \left[\frac{\left[\frac{{\left(m!\right)}^2}{m^3}\right]}{\frac{{\left(m!\right)}^2}{m^3}}\right]\right)}}{ 1 + \sum_{m=1}^i{\left(1 - \left[\frac{\left[\frac{{\left(m!\right)}^2}{m^3}\right]}{\frac{{\left(m!\right)}^2}{m^3}}\right]\right)}} \right]\times i \times \left(1 - \left[\frac{\left[\frac{{\left(i!\right)}^2}{i^3}\right]}{\frac{\left(i!\right)^2}{i^3}}\right]\right)\right)}\right)\times\left[\frac{\left[\frac{{\left(n!\right)}^2}{n^3}\right]}{\frac{{\left(n!\right)}^2}{n^3}}\right] + {\left(\sum_{i=1}^{2^k\times n}{\left(\left[\frac{1+\sum_{m=1}^{i}{\left(1 - \left[\frac{\left[\frac{{\left(m!\right)}^2}{m^3}\right]}{\frac{{\left(m!\right)}^2}{m^3}}\right]\right)}}{k + \sum_{m=1}^n{\left(1 - \left[\frac{\left[\frac{{\left(m!\right)}^2}{m^3}\right]}{\frac{{\left(m!\right)}^2}{m^3}}\right]\right)}} \right]\times \left[\frac{k + \sum_{m=1}^{n}{\left(1 - \left[\frac{\left[\frac{{\left(m!\right)}^2}{m^3}\right]}{\frac{{\left(m!\right)}^2}{m^3}}\right]\right)}}{ 1 + \sum_{m=1}^i{\left(1 - \left[\frac{\left[\frac{{\left(m!\right)}^2}{m^3}\right]}{\frac{{\left(m!\right)}^2}{m^3}}\right]\right)}} \right]\times i \times \left(1 - \left[\frac{\left[\frac{{\left(i!\right)}^2}{i^3}\right]}{\frac{\left(i!\right)^2}{i^3}}\right]\right)\right)}\right)\times \left(1 - \left[\frac{\left[\frac{{\left(n!\right)}^2}{n^3}\right]}{\frac{{\left(n!\right)}^2}{n^3}}\right] \right)} </math>
==dezyèm apròch==
| |||